MMpy.Project.open
Syntax
project.open(project_model_path)
Description
Opens a project.
Parameters
Name |
Type |
Description |
---|---|---|
project_model_path | str | The file path or name of a project. |
Returns
Type |
Description |
---|---|
bool | Returns True if successful, False otherwise. |
Examples
project = MMpy.Project() # By file path: project.open('C:\\data\\project_path') # Or by name: project.open('Examples 2018')
Resource ID
IDPH_PROJECT_OPEN